Answer : The concentration of final solution is, 0.197 M and the final volume of solution is, 400 ml
Solution :
First we have to calculate the final volume of solution.
Final volume of solution = Volume of [tex]MgSO_4[/tex] + Volume of water added
Final volume of solution = 225.0 ml + 175.0 ml = 400 ml
Now we have to calculate the concentration of final solution.
Formula used :
[tex]C_1V_1=C_2V_2[/tex]
where,
[tex]M_1[/tex] = concentration of [tex]MgSO_4[/tex] solution = 0.350 M
[tex]V_1[/tex] = volume of [tex]MgSO_4[/tex] solution = 225.0 ml
[tex]M_2[/tex] = concentration of final solution = ?
[tex]V_2[/tex] = volume of final solution = 400 ml
Now put all the given values in the above formula, we get the concentration of final solution.
[tex](0.350M)\times (225.0ml)=C_2\times (400ml)[/tex]
[tex]C_2=0.197M[/tex]
Therefore, the concentration of final solution is, 0.197 M
