Hello!
hint: we can rewrite your function as below:
3/tan(4x−3π) = 3(1+tan4xtan3π)/tan4x−tan3π =
=3/tan(4x) = 3cot(4x)
now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:
"4P=π"
Hope this Helps! Have A Wonderful Day! :)
