What is the area of this triangle?
A.) A=1/2(y3-y2)(x3-x1)
B.) A=1/2(y3-y1)(x3-x1)
C.) A=1/2(y3-y1)(x2-x1)
D.) A=1/2(y2-y1)(x3-x1)
E.) A=1/2(y2-y1)(x2-x1)

What is the area of this triangle A A12y3y2x3x1 B A12y3y1x3x1 C A12y3y1x2x1 D A12y2y1x3x1 E A12y2y1x2x1 class=

Respuesta :

The answer is D.) A=1/2(y2-y1)(x3-x1).
Explanation:
Area of a triangle equals side×height.
In this case height is x3-x1, and side y2-y1.

Answer:

Option D is correct

Step-by-step explanation:

[tex]\text{Given a triangle whose vertices are }(x_1, y_1), (x_1, y_2) , (x_3, y_3)[/tex]

we have to find the area of triangle.

As we know area of triangle can be calculated by the formula

[tex]\frac{1}{2}\times base\times height[/tex]

Base of triangle is the line joining the coordinates [tex](x_1, y_1), (x_1, y_2)[/tex] whose length is = [tex](y_2-y_1)[/tex]

Now height of triangle is the perpendicular line from the vertex [tex](x_3, y_3)[/tex] whose length is [tex](x_3-x_1)[/tex]

Hence, area of triangle is

[tex]\frac{1}{2}\times (y_2-y_1)\times (x_3-x_1)[/tex]

Option D is correct

Q&A Education