Respuesta :
y = 2/3x + 1
y = -2/3x - 1
----------------add
2y = 0
y = 0
0 = 2/3x + 1
-2/3x = 1
x = 1 * -3/2
x = -3/2
solution is : (-3/2,0)
y = -2/3x - 1
----------------add
2y = 0
y = 0
0 = 2/3x + 1
-2/3x = 1
x = 1 * -3/2
x = -3/2
solution is : (-3/2,0)
Answer:
Solution of the two equations is (-1.5,0)
Step-by-step explanation:
We are given two equations in the question:
[tex]y = \displaystyle\frac{2}{3}x + 1\\\\y = \displaystyle\frac{-2}{3}x - 1[/tex]
The attached image shows the solution for the two equation.
As seen from the graph the solution for the two equations is (-1.5,0)
Solving can be shown as:
[tex]y = \displaystyle\frac{2}{3}x + 1\\\\y = \displaystyle\frac{-2}{3}x - 1\\\\\text{Adding the two equations}\\\\2y = \displaystyle\frac{2}{3}x + 1 + \displaystyle\frac{-2}{3}x - 1 = 0\\\\\Rightarrow y = 0\\\text{Putting value of y in one of the equations, we get}\\\\0 = \displaystyle\frac{2}{3}x + 1\\\\x = \frac{-3}{2} = -1.5[/tex]
Thus, solution of the two equations is (-1.5,0)