Which linear inequality is represented by the graph? (A)y ≤1/3 x − 1 (B)y ≥ x − 1 (C)y < 3x − 1 (D)y > 3x − 1
Linear inequality represented by the graph is
[tex]\displaystyle (A)y\geq \dfrac{1}{3}x-1[/tex]
Straight-line equations are mathematical equations that are described in the plane of cartesian coordinates
General formula
[tex]\large{\boxed{\bold{y-y_1=m(x-x_1)}}[/tex]
or
Where
m = straight-line gradient which is the slope of the line
x1, y1 = the Cartesian coordinate that is crossed by the line
c = constant
The formula for a gradient (m) between 2 points
[tex]\large{\boxed{\bold{m=\dfrac{y_2-y_1}{x_2-x_1}}}[/tex]
If the intersection of the x-axis (b, 0) and the y-axis (0, a) then the equation of the line:
It says inequality if there are symbol forms like <, >, ≤ or ≥
Whereas linear inequality can have forms:
In graphical form, line inequality can be
For line inequality (positive coefficient y)
ax + by ≥ c then the solution is shaded upwards
ax + by ≤ c then the solution is shaded down
Or we input the values x, y from the point in the shaded area and put in the inequality line
From the picture we can determine the equation of the line
Line through 2 points (3,0) and (0,-1)
the gradient:
[tex]\displaystyle m=\frac{-1-0}{0-3}\\\\\displaystyle m=\frac{1}{3}[/tex]
the equation of the line: point (3,0)
[tex]\displaystyle y-0=\frac{1}{3}(x-3)\\\\\displaystyle y=\frac{1}{3}x-1[/tex]
We check the point in the area of shading, for example (0, 0)
we input in the equation :
[tex]\displaystyle 0=\frac{1}{3}.0-1\\\\0=-1[/tex]
Because 0 > -1 and the graph is solid line so the inequality line will be
[tex]\displaystyle (A)y\geq \dfrac{1}{3}x-1[/tex]
F (x) = x2 + 1 g (x) = 5 - x
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Keywords: linear inequality,graph
The equation of the line is [tex]\boxed{y \geqslant \frac{1}{3}x - 1}.[/tex]
Further explanation:
The linear equation with slope [tex]m[/tex] and intercept [tex]c[/tex] is given as follows.
[tex]\boxed{y = mx + c}[/tex]
The formula for slope of line with points [tex]\left( {{x_1},{y_1}} \right)[/tex] and [tex]\left( {{x_2},{y_2}} \right)[/tex] can be expressed as,
[tex]\boxed{m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}}[/tex]
Given:
Explanation:
The line intersects y-axis at [tex]\left( {0, - 1} \right)[/tex]. Therefore, the y-intercept is [tex]-1.[/tex]
The line passes through the points [tex]\left( {0, - 1} \right)[/tex] and [tex]\left( {3,0} \right).[/tex]
The slope can be obtained as follows,
[tex]\begin{aligned}m&= \frac{{0- \left( {- 1} \right)}}{{3 - 0}}\\&= \frac{1}{3}\\\end{aligned}[/tex]
Substitute [tex]\dfrac{1}{3}[/tex] for m, [tex]3[/tex] for [tex]x[/tex] and [tex]0[/tex] for [tex]y[/tex] in equation [tex]y = mx + c[/tex] to obtain the value of [tex]c[/tex].
[tex]\begin{aligned}0& \frac{1}{3} \cdot 3 + c\\- 1&=c\\\end{aligned}[/tex]
To check whether the equation includes origin substitute 0 for x and 0 for y in equation [tex]y \geqslant \dfrac{1}{3}x - 1.[/tex]
[tex]\begin{aligned}0&\geqslant \frac{1}{3} \times 0 - 1 \\0&\geqslant - 1\\\end{gathered}[/tex]
The statement is true. The equation contains origin.
The equation of the line is [tex]\boxed{y \geqslant \frac{1}{3}x - 1}.[/tex]
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Linear equation
Keywords: numbers,slope, slope intercept, inequality, equation, linear inequality, shaded region, y-intercept, graph, representation, origin.