Respuesta :
Given:
N: The numerator.
D: The denominator.
SOLVING:
[tex] \frac{N+3}{D}= \frac{3}{4}\ ===>\ Simplify[/tex]
4(N + 3) = 3D
4N + 12 = 3D
4N - 3D = - 12 ===> First equation.
[tex] \frac{N}{D-7}=1\ ===>\ Simplify[/tex]
N = 1(D - 7)
N = D - 7 ===> Second equation.
We replace the second equation in the first equation:
4(D - 7) - 3D = - 12
4D - 28 - 3D = - 12
D = - 12 + 28
D = 16 ===> The denominator.
N = 16 - 7
N = 9 ===> The numerator. SOLUTION
GOOD LUCK...!!!
N: The numerator.
D: The denominator.
SOLVING:
[tex] \frac{N+3}{D}= \frac{3}{4}\ ===>\ Simplify[/tex]
4(N + 3) = 3D
4N + 12 = 3D
4N - 3D = - 12 ===> First equation.
[tex] \frac{N}{D-7}=1\ ===>\ Simplify[/tex]
N = 1(D - 7)
N = D - 7 ===> Second equation.
We replace the second equation in the first equation:
4(D - 7) - 3D = - 12
4D - 28 - 3D = - 12
D = - 12 + 28
D = 16 ===> The denominator.
N = 16 - 7
N = 9 ===> The numerator. SOLUTION
GOOD LUCK...!!!