A country's population in 1992 was 72 million. In 1998 it was 76 million. Estimate the population in 2012 using the exponential growth formula. Round your answer to the nearest million.

formual: P=Ae^kt

Respuesta :

We assume the annual percentage increase is the same. We will work out the constant k using the formula

We have
P = 76
A = 72
t = 6 years (from 1992 to 1998)

Substitute into the formula
[tex]76=72e^{6k} [/tex]
[tex] \frac{76}{72}=e^{8k} [/tex]
Take log both sides give
[tex]ln( \frac{76}{72})=ln(e^{6k}) [/tex]
[tex]0.05406722127=6k[/tex]
[tex]k=0.009[/tex]

We can now work out the number of population by the end of 2012 using the formula

We have
A = 72 million
k = 0.009
t = 10 years (1992 to 2012)

[tex]P=72e^{0.009*10} [/tex][tex]P=78.78[/tex]≈79 million


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