[tex]\bf \textit{volume of a con}\\\\
V=\cfrac{\pi r^2 h}{3}\qquad
\begin{cases}
h=height\\
r=radius=\frac{diameter}{2}\\
d=diameter\\
----------\\
d=5.7\\
r=\frac{5.7}{2}=2.85\\
h=12
\end{cases}\implies V=\cfrac{\pi 2.85^2\cdot 12}{3}\\\\
-------------------------------\\\\[/tex]
[tex]\bf \textit{now, that's the original, now, let's scale "r" and "h" by 1.5}
\\\\\\
V=\cfrac{\pi r^2 h}{3}\qquad
\begin{cases}
r=2.85\cdot 1.5\\
h=12\cdot 1.5\\
----------\\
r=4.275\\
h=18
\end{cases}\implies V=\cfrac{\pi \cdot 4.275^2\cdot 18}{3}[/tex]
