Respuesta :

v=2.90 L
c=1.8 mol/L

n(NaOH)=vc

n(NaOH)=2.90L*1.8mol/L=5.22 mol
here is a couple of useful formula to use when you get problems like this.

[tex]Molarity= \frac{moles}{Liters} [/tex]        ----->      [tex]moles= (Molarity) x (Liters)[/tex]

since they are asking for moles, we are using the one on the right. 

Molarity= 1.8 M
Liters= 2.90 L

moles= (1.8 M) x (2.90 L)= 5.2 moles of NaOH


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