The root sof this quadratic equation are -4 and 2.5.
The roots of any quadratic can be found by using the quadratic equation. The equation is below for you.
[tex] \frac{-b +/- \sqrt{b^{2}- 4ac}}{2a} [/tex]
In this equation you use the number attached to x^2 as the a, which in this case is -2. The number attached to x as b, which is in this case -3. And the number at the end as c, which is 20. From there you solve for the answers.
[tex] \frac{3 +/- \sqrt{-3^{2}- 4(-2)(20)}}{2(-2)} [/tex]
[tex] \frac{3 +/- \sqrt{9 + 160}}{-4} [/tex]
[tex] \frac{3 +/- 13}}{4} [/tex]
Now you separate and get the two separate answers. First the positive.
[tex] \frac{3 + 13}}{4} [/tex]
[tex] \frac{16}}{4} [/tex]
4
Now the negative
[tex] \frac{3 - 13}}{4} [/tex]
[tex] \frac{-10}}{4} [/tex]
-2.5
