hbeck469 hbeck469

05-06-2017
Mathematics

contestada

The length of a rectangle is 2 more than three times the width. The area of the rectangle is 161 square inches. What are the dimensions of the rectangle? If x = the width of the rectangle, which of the following equations is used in the process of solving this problem? 2x2 + 3x - 161 = 0 3x2 + 2x - 161 = 0 6x2 - 161 = 0

Respuesta :

lizplllllllll lizplllllllll

05-06-2017

the explanation:
A= L*W
L= 2+3W
161=(2+3W)*(W)
=2W+2W^2 3W^2+2W-161

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culvecol culvecol

16-05-2019

Answer:

it is 3x2 + 2x - 161 = 0 or B

Step-by-step explanation:

Answer Link

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