1. P(getting all head)=[tex] \frac{n(getting-all-head)}{n(Sample-space)} [/tex]
2. Event: getting all head can happen in only one way: HHH
3. n(Sample space) can be calculated by
a. counting, a good ways to organize counting is drawing a tree diagram, CHECK THE PICTURE
or
b. There are 2 possible outcomes each time we throw the dice so 2*2*2=8 is the total number of outcomes, that is the number of the sample space.
4. So finally P(getting all head)=[tex] \frac{1}{8} [/tex]
