Respuesta :
distance from the point (x,y) to the focus = distance of (x,y) from the directrix
so we have
sqrt [(x - 2)^2 + y2] = 12 + y
squaring both sides
x^2 - 4x + 4 + y^2 = 144 + 24y + y^2
x^2 - 4x + 4 = 144 + 24y
24y = x^2 -4x - 140
y = x^2/24 - x/6 - 35/6 is the required equation
so we have
sqrt [(x - 2)^2 + y2] = 12 + y
squaring both sides
x^2 - 4x + 4 + y^2 = 144 + 24y + y^2
x^2 - 4x + 4 = 144 + 24y
24y = x^2 -4x - 140
y = x^2/24 - x/6 - 35/6 is the required equation
Answer:
f(x)= [tex]\frac{1}{24} x^2-\frac{1}{6}x-\frac{35}{6} \\[/tex] I just took the test and it is right
Step-by-step explanation:
