WILL GIVE BRAINLIEST

Quadrilateral ABCD underwent a sequence of transformations to give quadrilateral A′B′C′D′. Which transformations could have taken place?

A. a reflection across the x-axis followed by a reflection across the y-axis

B. a translation 10 units down followed by a translation 8 units to the right

C. a rotation 90° counterclockwise about the origin followed by a reflection across the y-axis

D. a reflection across the line y = x followed by a reflection across the line y = -x

The correct answer is B. This may seem tricky at first, but if you will notice how the units are marked, they are marked by 2s. Therefore the first figure moves down 5 blocks and over 4 blocks.

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dgsistemasp0pffb dgsistemasp0pffb · Answer 2 · 2019-08-30T09:40:31+02:00

Answer:

B. a translation 10 units down followed by a translation 8 units to the right.

Step-by-step explanation:

The translation rule is:

(x, y) -> (x + h, y + k)

Where

h = horizontal change

k = vertical change

According to the graph in the plane, we can calculate the original ABCD coordinates

A (-6, 4)

B (-6, 6)

C (-2, 6)

D (-4, 4)

While the coordinates after translation are:

A'(2, -6)

B'(2, -4)

C'(6, -4)

D'(4, -6)

Let's analyze the change of each coordinate:

For to:

2 - (- 6) = 8 --> 8 units to the right

-6 - 4 = -10 --> 10 units down

For B:

2 - (- 6) = 8 --> 8 units to the right

-4 - 6 = -10 --> 10 units down

For C:

6 - (- 2) = 8 --> 8 units to the right

-4 - 6 = -10 --> 10 units down

For D:

4 - (- 4) = 8 --> 8 units to the right

-6 - 4 = -10 --> 10 units down

Then the correct option is:

A translation 10 units down followed by a translation 8 units to the right.

Hope this helps!