we need a balanced equation:
C₃H₈ + 5O₂ ---> 3CO₂ + 4H₂O
let's convert the grams of water to moles using the molar mass. then mole-mole ratio to convert to moles of propane. finally, convert moles to Liters using the STP molar volume (1 mol= 22.4 L)
[tex]75 g H_2O ( \frac{1 mol H_2O}{18.02 grams} ) ( \frac{1 mol C_3H_8}{4 mol H_2O} ) ( \frac{22.4+ L}{1 mol} )= 23.3 L[/tex]
