Respuesta :
Slope simply put is the "rise over run" of an equation.
So, to find the "rise" you must first find the change in the y values:
212 - 32 = 180
Now for the "run" we do the same thing with the x values:
100 - 0 = 100
So, following the "rise over run" scenario we end up with [tex] \frac{180}{100} [/tex] which when simplified ends up being [tex] \frac{9}{5} [/tex]
So, to find the "rise" you must first find the change in the y values:
212 - 32 = 180
Now for the "run" we do the same thing with the x values:
100 - 0 = 100
So, following the "rise over run" scenario we end up with [tex] \frac{180}{100} [/tex] which when simplified ends up being [tex] \frac{9}{5} [/tex]
Answer:
[tex]m=\frac{9}{5}[/tex] or in decimal form [tex]m=1.8\\[/tex]
Step-by-step explanation:
Step 1: Find the slope
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
[tex]m=\frac{212-32}{100-0}[/tex]
[tex]m=\frac{180}{100}[/tex]
[tex]m=\frac{180/20}{100/20}[/tex]
[tex]m=\frac{9}{5}[/tex]
[tex]m=1.8\\[/tex]
Answer: [tex]m=\frac{9}{5}[/tex] or in decimal form [tex]m=1.8\\[/tex]