For Apex, the answers will be C & D.
(x-5)^2 + (y+7)^2 = 16
(x-3)^2 + (y+4)^2 = 1
The circles lie completely within the fourth quadrant C & D[tex](x-5)^2 + (y+7)^2 = 16\\(x-3)^2 + (y+4)^2 = 1[/tex]
If a circle O has a radius of r units length and it has got its center positioned at (h, k) point of the coordinate plane,
then, its equation is given as:
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
[tex]A. (x + 3)^2 + (y - 2)^2 = 25[/tex]
It doesn't lie in the fourth quadrant.
[tex]B. (x - 4)^2 + (y + 2)^2 = 32[/tex]
It doesn't lie in the fourth quadrant.
[tex]C. (x - 5)^2 + (y + 7)^2 = 16[/tex]
xc = (5) = 4
yc = -(-7) = -7
This equation lie in the fourth quadrant.
[tex]D. (x- 3)^2 + (y + 4)^2 = 1[/tex]
xc = (3) = +3
yc = -(-4) = -4
This equation lie in the fourth quadrant.
Therefore, The circles lie completely within the fourth quadrant C & D[tex](x-5)^2 + (y+7)^2 = 16\\(x-3)^2 + (y+4)^2 = 1[/tex]
Learn more about quadrant;
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