Find the radius and center of the circle given by the equation below.
(x – 6)2 + (y + 4)2 = 7

A. r = 7 and center at (-6, 4)

B. r = 7 and center at (6, -4)

C. r = √7 and center at (-4, 6)

D. r = √7 and (6, -4)

Respuesta :

the answer to your question is b

Answer:

D. r = √7 and (6, -4)

Step-by-step explanation:

Since, the standard equation of a circle is,

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Where, (h,k) is the center of the circle and r is the radius of the circle,

Here, the given equation of the circle,

[tex](x-6)^2+(y+4)^2=7[/tex]

[tex]\implies (x-6)^2+(y-(-4))^2=(\sqrt{7})^2[/tex]

By comparing,

The radius of the circle, r = √7 unit,

And, center = (6,-4)

Hence, option 'D' is correct.

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