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05-06-2017
Chemistry

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Find number of oxygen atoms in 0.25mole of ca3(po4)2

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dec77cat dec77cat

05-06-2017

n(Ca₃(PO₄)₂)=0.25 mol

n(O)=8n(Ca₃(PO₄)₂)

N(O)=Nₐn(O)=8Nₐn(Ca₃(PO₄)₂)

N(O)=8*6.022*10²³ mol⁻¹*0.25 mol=1.2044*10²⁴

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