The boy has to move the lever to 0.72 m to raise the rock a distance of 0.13 m.
An external force that acts upon an object results in a motion of the object, then it is called a work done upon the object by that force.
Given that the external force on a lever is 225 N and on a rock is 1250 N. The distance of motion by the rock is 0.13 m.
Hence the work done by the lever will be equivalent to the work done by the rock to move a particular distance.
Work (Lever) = Work (Rock)
[tex]F _l \times d_l = F_r \times d_r[/tex]
[tex]225\times d_l = 1250 \times 0.13[/tex]
[tex]d_l = 0.72\;\rm m[/tex]
Hence we can conclude that the distance of the motion by the lever is 0.72 m.
To know more about the work, follow the link given below.
https://brainly.com/question/3902440.
