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The specific heat of a substance is 2.01 j/g·°
c. if given 10.3 grams of the substance and if 542 joules of heat is absorbed, what is the change in temperature of the substance?

Respuesta :

angeljavier
The formula you need to use here is this one: Q = m × C × ΔT, where Q is heat, m is mass, C is specific heat, and ΔT is change in temperature. Plug in the values you are given and solve for ΔT algebraically!
(542) = (10.3)(2.01)(ΔT)
542 = (20.703)(ΔT)
26.2 = ΔT
Remember sig figs! All of the values given in the question have 3 significant figures each, so the final answer must have 3 as well. Therefore, you round and get 26.2 degrees Celsius (because temperature is measured in degrees Celsius) for the change in temperature. Hope that helps!

Answer:

The change in temperature is 26.4 C

Explanation:

Given:

Mass of the substance, m = 10.3 g

Specific heat of the substance, c = 2.01 J/g C

Heat absorbed, q = 542 J

To determine:

The change in temperature, ΔT

Explanation:

The amount of heat (q) absorbed (or evolved) by  a substance of mass (m) in order to bring a temperature change of (ΔT) is given as:

[tex]q = mc\Delta T[/tex]

[tex]\Delta T = \frac{q}{mc}[/tex]

In this case:

[tex]\Delta T = \frac{542 J}{10.2 g*2.01 J/gC}= 26.4 C[/tex]

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