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In triangle ABC, angle C is a right angle and BC=5. If measure of angle B = 30 degrees, find AC
a) sqrt3/5
b) 5/2
c) 5sqrt3/2
d) 5sqrt3/3

Respuesta :

Meli0406
answer = d

using the 30 - 60 - 90 triangle theorem

side across from the angle

across from angle 30 is x
across from angle 60 is x rad. 3
across from 90 is 2x

BC is across from angle 60
so BC is the x rad 3
set the given measurement equal to it

x sqrt 3 = 5
÷ sqrt 3 ÷ sqrt 3
x = (5/ sqrt 3)
multiply top and bottom by the radical to get rid of the radical in the bottom

x = (5/ sqrt 3) × (sqrt 3/sqrt 3)
x = 5 sqrt 3/ 3

since side BC is x
BC = 5 sqrt 3/ 3

* Drawing the triangle diagram would help*

The value of AC in the right angle triangle that has an angle of 30 degrees is 5√3 / 3

What is a right triangle?

A right triangle has one of its angles as 90 degrees. Therefore, the sides can be found using trigonometric ratios,

Hence,

tan 30° = opposite  /adjacent

tan 30° = AC / 5

cross multiply

AC = 5 tan 30°

AC = 5 × 1 / √3

AC = 5 / √3

Let's rationalise

AC = 5√3 / 3

learn more on right triangle here: https://brainly.com/question/12099532

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