Answer:
Attachment
Step-by-step explanation:
Given: [tex]f(x)=x^3-10x^2+9x[/tex]
This is cubic equation. We will find x and y intercept.
For x-intercept: Put y=0
[tex]x^3-10x^2+9x=0[/tex]
[tex]x(x^2-10x+9)=0[/tex]
[tex]x(x-9)(x-1)=0[/tex]
[tex]x=0,1,9[/tex]
x-intercepts: (0,0) (1,0) (9,0)
For y-intercept: Put x=0
[tex]f(0)=0^3-10\cdot 0^2+9\cdot 0=0[/tex]
y-intercept: (0,0)
End behavior : It is cubic equation and leading coefficient is 1.
Leading coefficient of is positive.
So, x → ∞ , y → ∞ and x → -∞ , y → -∞
Now, we will draw the graph using points and end behavior.
Please find attachment for graph.
