Respuesta :
a+s=496
s=496-a
and we are also told that:
s=3a
Since s=s we can say:
3a=496-a add a to both sides
4a=496 divide both sides by 4
a=124
So 124 adult tickets were sold.
s=496-a
and we are also told that:
s=3a
Since s=s we can say:
3a=496-a add a to both sides
4a=496 divide both sides by 4
a=124
So 124 adult tickets were sold.
since there were three times as many student tickets sold, you can write the equation C = 3A C being children tickets and A being adult tickets
to get the total number of tickets sold you add children and adults so the equation would be C + A = 496
this is a substitution problem. where you take what C equals in the first equation, and plug it into C for the second equation
(3A) + A = 496
4A = 496
A = 124
so you now know that 124 adult tickets where sold.
to get the total number of tickets sold you add children and adults so the equation would be C + A = 496
this is a substitution problem. where you take what C equals in the first equation, and plug it into C for the second equation
(3A) + A = 496
4A = 496
A = 124
so you now know that 124 adult tickets where sold.