Respuesta :

so called "rationalizing" it, is just getting rid of the pesky radical at the bottom

so   [tex]\bf \cfrac{4x}{\sqrt{3x+11}}\cdot \cfrac{\sqrt{3x+11}}{\sqrt{3x+11}}\implies \cfrac{4x\sqrt{3x+11}}{(\sqrt{3x+11})^2}\iff \cfrac{4x\sqrt{3x+11}}{\sqrt{(3x+11)^2}} \\\\\\ \cfrac{4x\sqrt{3x+11}}{3x+11}[/tex]
times whole thing by [tex] \frac{ \sqrt{3x+11} }{ \sqrt{3x+11} } [/tex]
we get
[tex] \frac{4 \sqrt{3x+11} }{3x+11} [/tex]
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