Respuesta :

Hope this helps.

Good luck mate :P
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Step-by-step explanation:

We have [tex]f(x)=y=4^x[/tex] and we need to graph this exponential function.

First we need to find the value of y when x=0, this is:

[tex]f(0)=4^0\\y=1[/tex]

Then the y value when x=0 is y=1. We have then the point (0,1). Which is the point A in the graph.

Now, we have to find the value of y with different values of x:

With x=1:

[tex]f(1)=4^1\\y=4[/tex]

We have the point (1,4). Which is the point B in the graph.

With x=-1:

[tex]f(-1)=4^-^1\\y=\frac{1}{4}=0.25[/tex]

We have the point (-1,0.25). Which is the point C in the graph.

With x=2:

[tex]f(2)=4^2\\y=16[/tex]

We have the point (2,16). Which is the point D in the graph.

With x=-2:

[tex]f(-2)=4^-^2\\y=\frac{1}{16} =0.0625[/tex]

We have the point (-2,0.0625). Which is the point E in the graph.

We can continue calculating y with differents values of x but with 5 points it's enough to graph.

Then the graph of [tex]f(x)=y=4^x[/tex] is:

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