Respuesta :

irspow
The quadratic formula used to solve a quadratic of the form ax^2+bx+c is:

x=(-b±√(b^2-4ac))/(2a) so in this case:

x=(3±√(9+8))/4

x=(3±√17)/4
(2x - 1)(x - 1) = 0 
by the zero property which must be stated!!!! 

2x-1=0 or x-1=0 

2x=+1 or x = +1 
x = 1/2 


a= 2 b = -3 c= +1 
+3+-√( 9 -4*2*1) / 4 
+3+-√ 1/4 
3+-1/4 = 1/2 or +1 as we found earlier

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