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A vehicle travels a distance of of 5t^4-10t^2+6 miles in t+2 minutes.

What is the vehicles speed?

A. 5t^3+10t^2+10t+20+(46)/(t-2))
B. 5t^3-10t^2+10t+20+46
C. 5t^3-10t^2+10t-20+(46)/(t+2))
D. 5t^3+10t^2+10t+20+(46)/(t+2))

Respuesta :

Speed = Distance / Time

Distance = 5t^4 - 10t^2+6

Time = t+2

Now:

 5t^4 - 10t^2 + 6         | t+2
-5t^4 -10t^3                 5t^3 - 10t^2 + 10t - 20
 \\\\\ -10t^3-10t^2+6
       +10t^3+20t^2
        \\\\\\\ 10t^2+6
                -10t^2-20t
                 \\\\\ -20t+6
                      +20t+40
                       \\\\\ 46

C. 5t^3-10t^2+10t-20+(46)/(t+2))
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