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What are the ratios for sin A and cos A? The diagram is not drawn to scale

A. sin A = 5/13, cos A = 12/13
B. sin A = 12/13, cos A = 5/13
C. sin A = 12/13, cos A = 5/12
D. sin A = 12/5, cos A - 5/14


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Please Help Will Give Brainiest Answer What are the ratios for sin A and cos A The diagram is not drawn to scale A sin A 513 cos A 1213 B sin A 1213 cos A 513 C class=

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kemanci
Remember soh cah toa when working wtih sines, cosines, and tangents.
Sine=opposite/hypotenuse; Cosine=adjacent/hypotenuse; tangent=opposite/adjacent
12 is opposite of a, and 13 is the hypotenuse. So the sin(a)=12/13
5 is adjacent to a, and 13 is the hypotenuse. So the cos(a)=5/12

Answer:

B. sin A = 12/13, cos A = 5/13

Step-by-step explanation:

The given triangle is a right triangle. In the right triangle, the hypotenuse = 13, Opposite side = 12 and Adjacent side = 5 with respect to the ∠A.

sin and cos are the trigonometric ratios.

sin = opposite / hypotenuse

cos = Adjacent /hypotenuse

With respect to ∠A.

sin A = Opposite /Hypotenuse.

Now plug in opposite side = 12 and hypotenuse = 13 to get sin A

sin A = 12/13

cos A = Adjacent/Hypotenuse.

Here adjacent side =5 and hypotenuse = 13.

So, cos A = 5/13

Therefore answer is B. sin A = 12/13, cos A = 5/13

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