A total of 6 family members will appear in a portrait. if 4 of the family members may sit in the front row how many combinations of family members may sit in the front row?

Respuesta :

The answer would be 15

Answer: 15

Step-by-step explanation:

The combination of n things  taken r at a time :-

[tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex]

Given : A total of 6 family members will appear in a portrait.

If 4 of the family members may sit in the front row , then the number of combinations of family members may sit in the front row is given by :-

[tex]^6C_4=\dfrac{6!}{4!(6-4)!}\\\\=\dfrac{6!}{4!2!}=15[/tex]

Therefore , the number of combinations of family members may sit in the front row =15

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