ReRe191
ReRe191
05-05-2017
Mathematics
contestada
Vertex of the parabola y=(x+4)^2-1
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mreijepatmat
mreijepatmat
06-05-2017
y=(x+4)²-1. Let's expand it: y=x²+8x+15.
This quadratic function intersects the x-axis at x₁ = - 3 & x₂ = - 5
Its axis of symmetry is x = - b/2a = ( - 8 )/2===> x = - 4
Now plug - 4 into the equation ===> y = -1
So the vertex is at (-4,1)
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