Answer:
[tex]\frac{1}{4}[/tex]
Step-by-step explanation:
When spinner is spun for the first time
Total events = {1,2,3,4,1,2,1,1} =8
Favorable events = {1,1,1,1} =4
So, probability = [tex]\frac{\text{Favorable outcomes }}{\text{Total outcomes}}[/tex]
So, probability of getting 1 = [tex]\frac{4}{8}[/tex]
= [tex]\frac{1}{2}[/tex]
When the spinner is spun for second time
Total events = {1,2,3,4,1,2,1,1} =8
Favorable events = {1,1,1,1} =4
So, probability = [tex]\frac{\text{Favorable outcomes }}{\text{Total outcomes}}[/tex]
So, probability of getting 1 = [tex]\frac{4}{8}[/tex]
= [tex]\frac{1}{2}[/tex]
So, probability that spinner will land on 1 both times : [tex]\frac{1}{2} \times\frac{1}{2}[/tex]
= [tex]\frac{1}{4}[/tex]
Hence the probability of hat spinner will land on 1 both times is [tex]\frac{1}{4}[/tex]
