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05-05-2017
Mathematics

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Q and R are mutually exclusive events. If P(Q)=3/4 and P(R)=1/6.
Find P(Q or R)

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LammettHash LammettHash

05-05-2017

Since [tex]Q[/tex] and [tex]R[/tex] are mutually exclusive, you get

[tex]\mathbb P(Q\cup R)=\mathbb P(Q)+\mathbb P(R)=\dfrac34+\dfrac16=\dfrac{11}{12}[/tex]

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