Answer:
75 milligrams.
Step-by-step explanation:
We have been given that Bismuth-210 has a half-life of about 5 days.
To solve our given problem we will use half-life formula.
[tex]y=a\cdot(\frac{1}{2})^{\frac{t}{b}}[/tex], where,
a = Initial value,
t = Time,
b = half-life.
Upon substituting our given values in above formula we will get,
[tex]y=600\cdot(\frac{1}{2})^{\frac{15}{5}}[/tex]
[tex]y=600\cdot(0.5)^{3}[/tex]
[tex]y=600\cdot 0.125[/tex]
[tex]y=75[/tex]
Therefore, 75 milligrams of Bismuth-210 will remain after 15 days.
