Answer : The molecular geometry of interior carbon atom is tetrahedral.
Explanation :
Now we have to determine the hybridization of the given molecule.
Formula used :
[tex]\text{Number of electron pair}=\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
The given molecule is, [tex]CH_3-CH_2-NH_2[/tex]
In this compound, the interior atom or central atom is carbon and [tex]CH_3[/tex], [tex]NH_2[/tex] and 2 hydrogen atoms are neighboring atoms.
[tex]\text{Number of electrons}=\frac{1}{2}\times [4+4]=4[/tex]
Number of bond pairs = 4
Number of lone pairs = 0
The number of electron pair are 4 that means the hybridization will be [tex]sp^3[/tex] and the electronic geometry and the molecular geometry of the molecule will be tetrahedral.
Hence, the molecular geometry of interior carbon atom is tetrahedral.
