Answer:
[tex]x_{1} = \frac{2+\sqrt{192}}{-4}; x_{2} = \frac{2-\sqrt{192}}{-4}[/tex]
Step-by-step explanation:
[tex]-2a^{2}-2b-12=0\\[/tex]
Take the coefficients and substitute for a, b and c
[tex]a = -2; b = -2; c = -12[/tex]
[tex]x_{1,2} = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}[/tex]
[tex]x_{1,2} = \frac{2+-\sqrt{2^2-4*-2*-12}}{2*-2}[/tex]
[tex]x_{1} = \frac{2+\sqrt{192}}{-4}[/tex]
[tex]x_{2} = \frac{2-\sqrt{192}}{-4}[/tex]
Please tell me if my solutions are incorrect so I can fix them.
