Respuesta :

Zero lines that are horizontal there slope is zero
To find the slope, we first need to find the midpoints of TV and UV.

TV
[tex] \frac{x1+x2}{2} , \frac{y1+y2}{2} [/tex]
[tex] \frac{-6+-3}{2} , \frac{-6+-2}{2} [/tex]
[tex] \frac{-9}{2} , \frac{-8}{2} [/tex]
=(-4.5,-4)

UV
[tex] \frac{-6+1}{2} , \frac{-2+-6}{2} [/tex]
[tex] \frac{-5}{2} , \frac{-8}{2} [/tex]
=(-2.5,-4)

Then we find the slope of this line.

[tex] \frac{-4-(-4)}{-2.5-(-4.5)} [/tex]
[tex] \frac{-4+4}{-2.5+4.5} [/tex]
[tex] \frac{0}{2} [/tex]

Since 0/2 is 0, the slope would be 0. (B)

:)
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