MeekaTheQueen
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Walt is wrapping a poster enclosed in a cylindrical tube. The tube has a diameter of 6 centimeters and a length of 50 centimeters. Find the amount of wrapping paper Walt needs. Round to the nearest tenth

Respuesta :

irspow
A=2pr^2+2prh  and r=d/2 so

A=(2pd^2)/4+(2pdh)/2

A=(2pd^2+4pdh)/4

A=(2pd/4)(d+2h)

A=(pd/2)(d+2h)

A=(6p/2)(6+2*50)

A=(3p)(106)

A=318p cm^2

A≈999.0 cm^2  (to nearest tenth of a square centimeter)
Barlosoffdaperc

Answer:

The answer is 26CM

Step-by-step explanation:

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