shannonangel
contestada

The bull's eye on an archery target has a radius of 3 inches. The entire target has a radius of 9 inches. To the nearest 10th, find the area of the target outside the bull's eye.

Respuesta :

coral5510
do 9 x 9=81 then 81 x 3.14 = 254.3 Then, 3 x 3= 9 then 9 x 3.14 =28.3 For the area around the bullseye do 254.3 - 28.3
The answer is 226

calculista

Answer:

[tex]226.1\ in^{2}[/tex]

Step-by-step explanation:

we know that

The area of the target outside the bull's eye is equal to the area of the entire target minus the area of the bull's eye

so

[tex]A=\pi (9^{2}-3^{2} )=72\pi=72(3.14)=226.1\ in^{2}[/tex]

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