Respuesta :
Answer : The volume of hydrogen gas formed at STP are, 8.557 liters
Explanation : Given,
Mass of zinc = 25.0 g
Molar mass of zinc = 65.38 g/mole
First we have to calculate the moles of zinc.
[tex]\text{Moles of }Zn=\frac{\text{Mass of }Zn}{\text{Molar mass of }Zn}=\frac{25g}{65.38g/mole}=0.382moles[/tex]
Now we have to calculate the moles of hydrogen gas.
The given balanced chemical reaction is,
[tex]Zn(s)+2HCl(aq)\rightarrow H_2(g)+ZnCl_2(aq)[/tex]
From the balanced chemical reaction, we conclude that
As, 1 mole of Zn react to give 1 mole of hydrogen gas
So, 0.382 mole of Zn react to give 0.382 mole of hydrogen gas
Now we have to calculate the volume of hydrogen gas.
At STP,
As, 1 mole of hydrogen gas contains 22.4 L volume of hydrogen gas
So, 0.382 mole of hydrogen gas contains [tex]0.382\times 22.4=8.557L[/tex] volume of hydrogen gas.
Therefore, the volume of hydrogen gas formed at STP are, 8.557 liters
