Respuesta :

brivera
let x be the first integer, then
:
x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 519
:
6x + 15 = 519
:
6x = 504
:
x = 84
6 consecutive integers
x, x+1, x+2, x+3, x+4, x+5

sum of 6 consecutive integers is 519
x+ x+1+ x+2+ x+3+ x+4+ x+5 = 519
6x + 15 = 519
6x = 504
x  = 84

84 +1 = 85
84 +2 = 86
84 +3 = 87
84 +4 = 88
84 +5 = 89

answer: third number in this sequence = 86

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