On May 22, 1960, an earthquake in Chile measured 9.5 on the Richter scale. On February 27, 2010, another earthquake in Chile measured 8.8 on the Richter scale. Compare the intensities of the two earthquakes. Round to the nearest whole number.

Respuesta :

Answer:

[tex]\frac{I_1}{I_2} =5[/tex]

Step-by-step explanation:

We can use Richter scale formula

[tex]R=log(I)[/tex]

where

I is intensity

R is Richter scale value

First case:

On May 22, 1960, an earthquake in Chile measured 9.5 on the Richter scale

so, we get

[tex]9.5=log(I_1)[/tex]

Second case:

On February 27, 2010, another earthquake in Chile measured 8.8 on the Richter scale

so, we get

[tex]8.8=log(I_2)[/tex]

we can subtract both equations

[tex]9.5-8.8=log(I_1)-log(I_2)[/tex]

[tex]log(\frac{I_1}{I_2} )=0.7[/tex]

[tex]\frac{I_1}{I_2} =10^{0.7}[/tex]

[tex]\frac{I_1}{I_2} =5[/tex]

The comparison of the intensities of the two earthquakes will be equal to I1/I2=5. We know that magnitude of the earthquake is expressed on a numerical scale that is based on seismograph oscillations.

What is the Richter scale?

The magnitude of the earthquake is expressed on a numerical scale which is based on seismograph oscillations. Richter scale is a logarithmic scale.

We can use the Richter scale formula

[tex]\rm R= log(I)[/tex]

where I is intensity and R is the Richter scale value

First case:

On May 22, 1960, an earthquake in Chile measured 9.5 on the Richter scale

so, we get

[tex]\rm 9.5= Log(I_1)[/tex]

Second case:

On February 27, 2010, another earthquake in Chile measured 8.8 on the Richter scale

so, we get

[tex]\rm 8.8=Log(I_2)[/tex]

we can subtract both equations

[tex]\rm 9.5-8.8=Log(I_1)-Log(I_2)\\\\\\Log\dfrac{I_1}{I_2}=0.7\\\\\\\dfrac{I_1}{I_2}=10^{0.7}\\\\\\\dfrac{I_1}{I_2}=5[/tex]

Hence the comparison of the intensities of the two earthquakes will be equal to I1/I2=5

To know more about the Richter scale follow

https://brainly.com/question/24256134

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