Respuesta :
To determine the mass of sucrose from a given volume of solution, we need to convert the volume into mass by using the density of the solution. We calculate as follows:
mass solution = 3.50 ( 1118 ) = 3913 g
mass of sucrose = 3913 g solution ( .485 g sucrose / g solution ) = 1897.805 g sucrose is present in the solution.
mass solution = 3.50 ( 1118 ) = 3913 g
mass of sucrose = 3913 g solution ( .485 g sucrose / g solution ) = 1897.805 g sucrose is present in the solution.
Answer: The mass of sucrose in the given volume of solution is 1897.92 grams.
Explanation:
We are given:
Mass percent of sucrose is 48.5 %. This means that 48.5 grams of sucrose is present in 100 grams of solution.
Density of solution = 1.118 g/mL
To calculate volume of a substance, we use the equation:
[tex]Density=\frac{Mass}{Volume}[/tex]
Putting values in above equation, we get:
[tex]1.118g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=89.44mL[/tex]
We need to find the mass of sucrose present in 3.50 L or 3500 mL of solution, we apply unitary method:
In 89.44 mL of volume, the mass of sucrose present is 48.5 grams.
So, in 3500 mL of solution, the mass of sucrose present will be [tex]\frac{48.5g}{89.44mL}\times 3500mL=1897.92g[/tex]
Hence, the mass of sucrose in the given volume of solution is 1897.92 grams.