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There are two distinct shapes in this polygon: triangle on top and square on bottom.  Find the areas of them separately and then add together.  Triangle length is 7cm x height is 3 cm (11cm - 8cm). Then divide by 2. Square is 7cm x 8cm.  Solve those two then add together.

The area is the space used by a two-dimensional object.

The area of the given figure is 66.5 square cm.

How do you calculate the area of the given object?

Given that the object has a base b of 7 cm, height h of 11 cm and length l is 8 cm.

To calculate the area of the given object, let us divide the object into two parts. The attachment shows the resultant object which has two parts, a rectangle whose length and width are 8 cm and 7 cm and a triangle whose base is 7 cm and height is 3 cm.

The total surface area of the object is sum of the surface area of rectangle and area of  triangle.

The area of rectangle is given below.

[tex]A (\rm Rectangle) = l\times w[/tex]

[tex]A (\rm Rectangle ) = 8\times 7[/tex]

[tex]A (\rm Rectangle ) = 56 \;\rm cm^2[/tex]

The area of the triangle is given below.

[tex]A (\rm Triangle) = \dfrac {1}{2}\times b\times h[/tex]

[tex]A (\rm Triangle) = \dfrac {1}{2}\times 7\times 3[/tex]

[tex]A (\rm Triangle) = 10.5 \;\rm cm^2[/tex]

The total area of the object is given below.

Area A = A (Rectangle) + A (Triangle)

[tex]A = 56 +10.5[/tex]

[tex]A = 66.5 \;\rm cm^2[/tex]

Thus, the total surface area of the object is 66.5 square cm.

To know more about the area, follow the link given below.

https://brainly.com/question/1631786.

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