ok, under the assumption that the problem is
[tex]25^x = 5^{x-2}[/tex]
as opposed to
[tex]25^x = 5^x-2[/tex]
[tex]25^x = 5^{x-2}[/tex]
looking the the left side
25 = 5^2 so the left side can be written as
[tex](5^2)^x = 5^{x-2}[/tex]
now, if you remember exponent rules, a power to a power, you just multiply them together
so it would be equal to this equation
[tex]5^{2x} = 5^{x-2}[/tex]
now, since they share the same base (5)
you can jsut compare the exponents
2x= x-2
and then solve for x
trying to solve
[tex]25^x = 5^x-2[/tex]
requires the use of log i believe
