Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. x+y = 3, x = 4−(y−1)^2; about the x-axis.
The intersection between the curves are 3, 0 0, 3 The volume of the solids is obtained by V = ∫ π [ (4 - (y-1)²)² - (3 - y)²] dy with limits from 0 to 3 The volume is V = 108π/5 or 67.86
