Start off by combining like terms on the LHS (the terms with x in them).
So we get [tex] \frac{-1}{3}x+2x= \frac{-1}{3}x+ \frac{6}{3}x= \frac{-5}{3}x [/tex]
Replacing this result with what we had before on the LHS, we get [tex] \frac{-5}{3}x=3 \frac{3}{4}= \frac{9}{4} [/tex]
⇒Solve for x (divide both sides [tex] \frac{-5}{3} [/tex])
⇒Don't forget about reciprocity rules when dividing. This is the same as multiplying both sides by [tex] \frac{3}{-5} [/tex]
⇒[tex]x= \frac{9}{4}( \frac{3}{-5})
[/tex]
⇒[tex]x= -\frac{27}{20}=-1\frac{7}{20}[/tex] ***This is a proper fraction
