What is the equation of the line in slope intersect form that passes through point (3,-2) and it’s parallel to the line y=2x+4? Show all necessary steps.

Respuesta :

Answer: y = 2x - 4

Step-by-step explanation:

First you find the parallel slope. It's 2, as shown in the slope-intercept equation you provided.

Now you have to use point-slope form where m is slope, y1 is a y-coordinate and x1 is an x-coordinate:

[tex]y - y_1 = m(x - x_1)[/tex]

to find the line using the slope of 2 and the point (3, -2)

You plug in everything and get:

y - (-2) = 2 ( x - 3 )

y + 2 = 2 ( x - 3 )

y + 2 = 2x - 6

y = 2x - 4

Answer:

[tex]y=2x-8[/tex]

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}[/tex]

The slope of the given line y = 2x + 4 is 2.

Parallel lines have the same slope.

Therefore, the slope of the line parallel to the given line is also 2.

Substitute the found slope and the given point (3, -2) into the slope-intercept formula and solve for b:

[tex]\implies -2=2(3)+b[/tex]

[tex]\implies -2=6+b[/tex]

[tex]\implies -2-6=6+b-6[/tex]

[tex]\implies -8=b[/tex]

[tex]\implies b=-8[/tex]

Substitute m = 2 and b = -8 into the slope-intercept formula to create the equation of the line that is parallel to the given line and that passes through the point (3, -2):

  • [tex]y=2x-8[/tex]
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