Two balls collide head-on on a table. The first ball has a mass of 0. 50 kg and an initial velocity of 12. 0 m/s. The second ball has a mass of 0. 75 kg and an initial velocity of -16. 0 m/s. After the collision, the first ball travels at a velocity of -21. 6 m/s. What is the velocity of the second ball after the collision? assume a perfectly elastic collision and no friction between the balls and the table.

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contexto1025 contexto1025 · Answer 1 · 2022-12-07T18:45:48+01:00

The velocity of the second ball after the collision is 2.8m/sec if both first and second ball collide head-on a table.

We are given that there is no role of friction and collision is perfectly elastic, it means momentum conservation is possible.

Since, all collision is happening along a single axis. So, we assume all collision is happening in x-axis.

Now, we need to conserve momentum along x-axis which states that initial momentum of the system is equal to final momentum of the system.

Now, we know that momentum is given by the product of mass and velocity.

So, initial momentum of the first ball is =0.50×12=6.00kg-m/sec

initial momentum of the second ball is=0.75×(-16.0)= -12.00kg-m/sec

Final momentum of first ball is =0.50 × (-21.6)m/sec = -10.8kg-m/sec

Final momentum of second ball =0.75×vkg-m/sec

Therefore, 6+(-12) = (-10.8) +(0.75v)

=> -6 =-10.8+0.75v

=>0.75v=10.8-6

=>0.75v=4.8

=>v=4.8/0.75

=>v=2.8m/sec

Hence, velocity of second ball is 2.8m/sec.

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