If a Triangle ΔABC has a perimeter of 38 and AC≅DC as well as BD≅BA than the side DC can be measures as CD=38-AB-BC if AB and BC are given.
A triangle is a three-sided polygon, which has three vertices. The three sides are connected with each other end to end at a point, which forms the angles of the triangle. The sum of all three angles of the triangle is equal to 180 degrees.
In the case of a triangle, the perimeter will be the sum of all the three sides. If a triangle has three sides a, b and c, then, Perimeter, P = a + b +c
As the perimeter of a triangle ABC is
Perimeter=AB+BC+CA
And we are given with only the perimeter of triangle;
P=38m
Now;
As given condition is;
AB=BD, AC=CD So;
38=AB+BC+CD
And
CD=38-AB-BC
If then length of the sides of AB and BC are provided we can calculate the value of CD
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